Benzene + (CH_3)_3C-CH_2Cl xrightarrow{AlCl_ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The reaction is a Friedel-Crafts alkylation. The alkyl halide is $(CH_3)_3C-CH_2Cl$ (neopentyl chloride). When $AlCl_3$ acts on this primary alkyl

Vedclass · Accepted Answer

tert-Pentylbenzene

Vedclass · Answer

(D) The reaction is a Friedel-Crafts alkylation. The alkyl halide is $(CH_3)_3C-CH_2Cl$ (neopentyl chloride). When $AlCl_3$ acts on this primary alkyl halide,it forms a carbocation intermediate. Initially,a primary carbocation $(CH_3)_3C-CH_2^+$ is formed,which is highly unstable. It immediately undergoes a $1,2-$methyl shift to form a more stable tertiary carbocation $(CH_3)_2C^+-CH_2-CH_3$. This tertiary carbocation then attacks the benzene ring to form the major product,which is tert-pentylbenzene ($2$-methyl$-2-$phenylbutane).

Benzene $ + (CH_3)_3C-CH_2Cl \xrightarrow{AlCl_3} \text{Major product}$

Similar Questions

Among the following,the set which represents aromatic species is:

Which of the following is nonaromatic in nature?

Which compound is formed when benzene is heated with chlorine in the presence of sunlight?

In the given compounds,the correct order of reactivity in electrophilic substitution reactions will be:

When benzene is treated with excess of $Cl_2$ in the presence of $FeCl_3$ (or $I_2$ as a carrier),the end product is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module